i see such possible scenario:
1. /usr/bin/foo owned by foo.x86_64 2. /usr/bin/foo owned by foo.i686 3. /usr/bin/foo owned by foo.x32
and i would prefer if it worked identically to: 1. /usr/bin/foo owned by foo.x86_64 2. /usr/bin/foo owned by foo.i686
i.e:
1. all three packages are installable, no file-conflict error 2. some preference of which binary will be placed
for x86_64 vs x32/i686 it's simple, but if i have x32 vs i686 binaries to decide, which one will "win"? x32 probably? or i686?
i see such possible scenario:
1. /usr/bin/foo owned by foo.x86_64
2. /usr/bin/foo owned by foo.i686
3. /usr/bin/foo owned by foo.x32
and i would prefer if it worked identically to:
1. /usr/bin/foo owned by foo.x86_64
2. /usr/bin/foo owned by foo.i686
i.e:
1. all three packages are installable, no file-conflict error
2. some preference of which binary will be placed
for x86_64 vs x32/i686 it's simple, but if i have x32 vs i686 binaries to decide, which one will "win"? x32 probably? or i686?