From my understanding the | T is implicit in the code as the symbol will already include the bit set. Indeed, the symbol address is extracted from the symbol table where the bit 0 is already set for thumb function.
Do you have a testcase you could share with us so that we can reproduce the issue?
Hi Pulin,
From my understanding the | T is implicit in the code as the symbol will already include the bit set. Indeed, the symbol address is extracted from the symbol table where the bit 0 is already set for thumb function.
Do you have a testcase you could share with us so that we can reproduce the issue?
Best regards.